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Mathematics 16 Online
OpenStudy (vera_ewing):

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OpenStudy (loser66):

what is the equation? \(2^y = 3~~or 2^y =x??\)

OpenStudy (loser66):

That is \(log_2 3 =y\) and its graph is a line.

OpenStudy (loser66):

Can't be one of the options.

OpenStudy (loser66):

If the question is \(2^y =x \\y = log_2 x\) then, we can consider it is a function of x. But your equation is y = a number, not a function. Therefore, if it has a graph, the graph must be a horizontal straight line, not a curve as shown.

OpenStudy (loser66):

Or!! my knowledge is not enough to solve. I am sorry. Let's wait for @ganeshie8

Parth (parthkohli):

The given graph must be a graph of \(f(x) = \log_2 x\) so that you can check its value at \(x=3\) and thus find \(y\), as Loser66 said. What properties of the \(\log_2 x\) can you think about that can help us eliminate the wrong choices? I'll start: it is not defined at \(x=0\), so it never crosses the line \(x=0\) (which is what you may know as the y-axis).

Parth (parthkohli):

Why can't it be B or C?

Parth (parthkohli):

They never really cross the line \(x=0\)... they're only moving along it. The curve will get reaaaaaaaally close to \(x=0\) but never will it touch it.

Parth (parthkohli):

Why not A or B or D?

Parth (parthkohli):

I'm not convinced.

Parth (parthkohli):

Did she mention why it's C?

Parth (parthkohli):

Why?

Parth (parthkohli):

Do you know who to evaluate \(f(x) = \log_2 x \) at different points? Basically do you know how the log function works?

Parth (parthkohli):

how*

Parth (parthkohli):

Have you been taught about graphing functions?

Parth (parthkohli):

And do you know about the logarithmic function?

Parth (parthkohli):

Well, if for instance, I ask you what \(\log(1)\) is... what is it?

Parth (parthkohli):

What?

Parth (parthkohli):

How?

Parth (parthkohli):

Why did you choose C?

Parth (parthkohli):

Well, why did you choose A?

Parth (parthkohli):

You shouldn't do that. For instance, the graph given in A crosses the y-axis.

Parth (parthkohli):

C is correct simply because it is the graph of \(f(x) = \log_2 x \).

OpenStudy (vera_ewing):

That's what I thought, but you didn't confirm!

OpenStudy (phi):

you want to chooses the graph that plots log base 2(x) you should look for the graph that goes through y=0 when x=1 and y=1 when x=2

OpenStudy (phi):

and y=2 when x= 4

Parth (parthkohli):

You know that \(2^y = 3\) so \(y = \log_2 3\). Now you can graph \(f(x) = \log_2 x\) and find the value of \(f(x)\) at \(x = 3\).

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