The sides of a square are 2 to the power of 4÷9 inches long. what is the area of the square?
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Vocaloid (vocaloid):
side = 2^(4/9)
area = side^2 = ?
OpenStudy (anonymous):
Wait what
OpenStudy (anonymous):
How can I solve this??? @vocaloid
Vocaloid (vocaloid):
it gives you the length of one side, so to find the area, you just square the length
(side)*(side) = 2^(4/9) * 2^(4/9) = ?
OpenStudy (anonymous):
Do I times it 4 times or just twice @vocaloid
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Vocaloid (vocaloid):
twice..
OpenStudy (anonymous):
@vocaloid
OpenStudy (anonymous):
I got 4 to the power of 16/81
Vocaloid (vocaloid):
not quite, we have to use the exponent rule here
keep the base and add the exponents together
2^(4/9) * 2^(4/9) = 2^(4/9 + 4/9) = ?
OpenStudy (anonymous):
Oh ok
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OpenStudy (anonymous):
Now I got 2 to the power of 8/9
OpenStudy (anonymous):
Is that right? @vocaloid
Vocaloid (vocaloid):
yes, sorry for the late reply
OpenStudy (anonymous):
Do you you think you can help me with another question? @vocaloid
Vocaloid (vocaloid):
sure
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OpenStudy (anonymous):
Given the function f(x) = 5^x , section A is from = x = 0 to x = 1 and the section B is from x = 2 to x = 3.
Part A: Find The average rate of change of each section
Part B: How many times greater is the average rate of change of section B then section A? Explain why one rate of change is greater than the other. @vocaloid
Vocaloid (vocaloid):
part A)
we want two values
1. the rate of change between x = 0 and x = 1
and
2. the rate of change between x = 2 and x = 3
so, let's just tackle the first part for now
the rate of change between x = 0 and x = 1 can be found using the formula
[f(1)-f(0)]/(1-0)
OpenStudy (anonymous):
I got one
Vocaloid (vocaloid):
not quite, let's take it bit by bit
f(1) = ?
OpenStudy (anonymous):
Is it one
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Vocaloid (vocaloid):
not quite
f(x) = 5^x
f(1) = ?
OpenStudy (anonymous):
5 to the power of one
Vocaloid (vocaloid):
right
now f(0) = ?
OpenStudy (anonymous):
5 to the power of zero
Vocaloid (vocaloid):
right, so
[f(1)-f(0)]/(1-0) = ?
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OpenStudy (anonymous):
Is it 1/1
Vocaloid (vocaloid):
no...
remember, we just calculated f(1) and f(0)
f(1) - f(0) = ?
OpenStudy (anonymous):
5^1 - 5^0
Vocaloid (vocaloid):
right, so
[f(1)-f(0)]/(1-0) = ?
OpenStudy (anonymous):
Do I have to solve the exponent
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Vocaloid (vocaloid):
yes
OpenStudy (anonymous):
5-1/ 1-0 = 4/1
Vocaloid (vocaloid):
right, and 4/1 = ?
OpenStudy (anonymous):
4
Vocaloid (vocaloid):
right, now let's calculate the rate of change from x = 2 to x = 3
[f(3)-f(2)]/(3-2) = ?
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OpenStudy (anonymous):
5^3 - 5^2/ 3-2
Vocaloid (vocaloid):
right, keep going...
OpenStudy (anonymous):
125 - 25/ 3-2
Vocaloid (vocaloid):
right, keep going...
OpenStudy (anonymous):
100/1= 100
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Vocaloid (vocaloid):
right
Vocaloid (vocaloid):
now we're finished w/ part A
part B wants us to find (rate of change from x = 2 to x = 3)/(rate of change from x = 1 to x = 2)
using what we calculated earlier...
100/4 = ?
OpenStudy (anonymous):
25
Vocaloid (vocaloid):
right so section B is 25 times as great (24 times greater) as section A
OpenStudy (anonymous):
So that's the answer
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Vocaloid (vocaloid):
as for "explain why" I would say something along the lines of
"f(x) is an increasing exponential function