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Mathematics 23 Online
OpenStudy (anonymous):

Verify the identity. Show your work. 1 + sec2xsin2x = sec2x the answer is 2

OpenStudy (anonymous):

Teacher:Substitute for the sec^2x on the RHS only. This is a reciprocal function. You should be able to take this from here. Me: wtf?

OpenStudy (anonymous):

@thomaster

OpenStudy (anonymous):

@Etrainx

OpenStudy (anonymous):

@Zale101

OpenStudy (anonymous):

I think somebody already answered this oooover here http://openstudy.com/study#/updates/509f00d7e4b013fc35a19250

OpenStudy (anonymous):

i used that one but my teacher said that up there so im confuzled

OpenStudy (anonymous):

@mukushla

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

@poopsiedoodle

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (anonymous):

@Vocaloid

OpenStudy (anonymous):

@Vocaloid can you give me some understanding of my teachers words plz

Vocaloid (vocaloid):

sec^2(x) = 1/(cos^2(x))

Vocaloid (vocaloid):

that's basically what she's saying, substitute 1/(cos^2(x)) for sec^2(x) on the right side

OpenStudy (anonymous):

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