Question

YAS

Answer 1

@welshfella @Hero @acxbox22 @LegendarySadist @prowrestler @Zale101 @xavierbo2 @campbell_st @vera_ewing @bubbleslove1234

Answer 2

@ikram002p @IrishBoy123 @imqwerty @AliceCullen @sammixboo

Answer 3

@nincompoop @nuccioreggie

Answer 4

ok, what is a simply linear equation...?

Answer 5

y=5x+3

Answer 6

next, what is a simple quadratic equation...?

Answer 7

16x^2+4x+2

Answer 8

what do I do now?

Answer 9

hello? @campbell_st

Answer 10

well I wouldn't have considered the 2 equations simple...

the quadratic is positive definite.... which means it won't cut the x-axis

by anyway, you have 2 equations...

next step is to solve them simultaneously

y = 5x + 3

y = 16x^2 + 4x + 2

so to solve them just equate them

5x + 3 = 16x^2 + 4x + 2

then solve for x.

but you have chosen 2 difficult equations...

I've attached a file, its a graph of your 2 equations

Answer 11

so you may want to rethink your equations.

Answer 12

i just made up 2 random equations
I don't know what equations to think of

Answer 13

ok... so start with simple

you linear equation is almost ok

change the y-intercept to 6

so use

y = 5x + 6

now a really simply quadratic is

\[y = x^2\]

So equating them you get

\[5x + 6 = x^2\]

or

\[x^2 - 5x - 6 = 0\]

this is a quadratic equation that can be solved by factoring...

so that is what you need to do, solve for x,

when you get the 2 answers, substitute the x values into either equation to find the matching y values...

so you will have 2 point of intersection...

if you have to graph the curves

1 use a table of values that includes both x values

or just just some graphing software line

https://www.desmos.com/calculator

Answer 14

thank you! @campbell_st