Question

Find the inverse of y=log base2 (x-5)+2.

Answer 1

first step swap x and y \[\huge\rm x =\log_2 (y-5)+2\]
now try to solve for y

Answer 2

move the 2 to the left side and then convert log to exponential form

Answer 3

I'm getting stuck after 2^log base2 (y-5) which is equal to y-5

Answer 4

i'm sorry what do you mean by 2^log ?

Answer 5

so yes technically it looks like this x+2 = y-5 then x = y-3.

Answer 6

2 to the power of log_2 (y-5) is equal to y - 5 after raising 2 to each side

Answer 7

well you have to move 2 to the left side so subtract 2 both sides \[\huge\rm x =\log_2 (y-5)+2\]
\[\huge\rm x-2=\log_2(y-5)\] right ? now convert log to exponential form

Answer 8

the*

Answer 9

that's how you should convert log to exponential form