Question

There are 6 red marbles, 9 blue marbles, and 10 green marbles in a bag.

What is the theoretical probability of randomly drawing a red marble and then a green marble?

Answer 1

depends entirely on whether you replace the marble or not after the first one is drawn

Answer 2

The first one is not replaced.

Answer 3

oh wait NOT replaced lets go slow

Answer 4

what is the probability the first one is red?

Answer 5

i hope that is more or less obvious
it is the ratio of the number or red marbles to the total number of marbles

Answer 6

24%?

Answer 7

There are 4 answers:

10%
9.6%
16%
64%

Answer 8

not really interested in percents before we compute these numbers
we need fractions first, then we can turn the final answer in to a percent

Answer 9

\[\frac{ 24 }{100}?\]

Answer 10

lets go slow
how many red marbles are there?

Answer 11

6

Answer 12

yes, and how many marbles are there total?

Answer 13

25

Answer 14

right
so the probability of picking a red marble first is
\[\frac{6}{25}\]

Answer 15

now the red marble is chosen, and apparently not replaced
how many green marbles are there ?

Answer 16

10

Answer 17

and how many marbles are left in the bag?

Answer 18

24

Answer 19

so the probability of picking a green marble once one red one is removes is?

Answer 20

\[\frac{ 10 }{ 24 }\]?

Answer 21

yes

Answer 22

to compute the probability that both things occur, multiply

Answer 23

\[\frac{6}{25}\times \frac{10}{24}\]

Answer 24

\[\frac{ 60 }{ 600 }\]

Answer 25

better known on planet earth as \(\frac{1}{10}\)

Answer 26

or \(0.1\) or even \(10\%\)

Answer 27

So that's the answer?