Consider the following unbalanced redox reaction: MnO4 � (aq) plus Sb H2 (aq) yields Mn O2 (s) plus Sb (s) What is being reduced?
is it Mn04
MnO4- SbH3 MnO2 Sb these are the options btw
First try balancing the equation
ok i did what was ur final answer im so confused that i need more guidance
just wait
a sec
ok
We'll delete one option first i.e SbH3
yes that is clear . wouldnt that be the oxidizing agent
But there is no SbH3 there in the qn right?
sorry i meant SB
what is the oxidizing agent in this equation
reducing agent is substance which get oxidized itself by giving electron
so Mn02 is the answer
right ?
I think so can you wait for sometime i'll check back to you after referring to some books thanks
ok
ok so this is simple. Keep this in mind Reduction means there will be a decrease in the product from the reactant Oxidation means there will be an increase in the product
So as far as the qustion is concerned, Mno4 gets reduced to MNO2 and Sbh2 to Sb. So both Sb and O2 get reduced. Since the options given to you do not have O2, go for Sb
and that makes the oxidizing agent to be mn04-
?
vice versa of agents Oxidising agent Decreases and Reducing agent increases
so its MnO4
Have you understood? i think you are confused
OK I'll explain the entire thing with another example.
You need not learn any definition byheart, just understand these simple procedures that i tell you
So i said Oxidising agent means there will be a decrease in the product Reducing agent means there will be an increase in the product
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