Question

My last question, any help?

Answer 1

How do you solve this?

Answer 2

hint:
by definition, we can write this:
\[\Large \left( {g \circ f} \right)\left( x \right) = g\left( {f\left( x \right)} \right)\]

Answer 3

Just taking a wild guess here, but would that make the answer D?

Answer 4

It is not.

Answer 5

\[If f(x)=3x^2-2x-1\]
and \[ g(x)=x^2\]
Since (x) in g(x) got replaced by a f(x) and \[f(x)=3x^2-2x-1\]

Answer 6

then \[3x^2-2x-1 \]
would replaced the x in
\[g(x)=x^2\]

Answer 7

which leads to \[(3x^2-2x-1)^2\]
g o f means g has a f inside that leads to g(f(x)) meaning the g(x) needs to be plugged in with f(x) instead.