Question

Find general solution of \(x\) in the equation :- \[sin6x=sin4x-sin2x\]

Answer 1

hint:
your equation, can be rewritten as follows:
\[\Large \sin \left( {4x} \right) = \sin \left( {6x} \right) + \sin \left( {2x} \right)\]

Answer 2

\[\sin4x=2\sin4xcos2x\]\[\sin4x(1-2\cos2x)=0\]\[x=\frac{n \pi}{4}\]&\[2x=2n \pi \pm \frac{\pi}{3}\]\[x=n \pi \pm \frac{\pi}{6}\]

Answer 3

yes! exact that was my idea

Answer 4

thanx

Answer 5

:)