Simplify root(1-sintheta)(1+sintheta)
\[\sqrt{(1-sin{\theta})(1+sin{\theta})}\] ?
Is that what you meant?
Yup
±sin θ cos θ ±tan θ square root sine theta
those are the answerscan u help me
\(\sqrt{(1-sin{\theta})(1+sin{\theta})}\) \(\sqrt{(1-sin^2{\theta })}\) But \(cos^2{\theta} + sin^2{\theta} = 1\), then \(\sqrt{cos^2{\theta}}\) \(\pm cos{\theta}\)
so would the answer be costheta only
yes
omg thank you can u help me with one more only
sure^^
@M4thM1nd
\(cos(x-\pi/2) = sin(x)\) and \(sin(x - \pi/2)=-cos(x)\)
So, which one you think is the right answer?
1st one
i think ... idk
No. From the graph we see that f(x) at x = 0 is 0, that means f(x) is some function of sin(x), since sin(x) at x = 0 is 0
so the answer is a
In that case, the first one we have \(sin(x-\pi/2) = -cos(x)\), so that can't be the right answer
okay the right answer is ...
If we check the last option, we have \(cos(x-\pi/2) = sin(x)\), but from the graph we also get the information that f(x) at x = pi/2 is equal to -4. But sin(x) at x = pi/2 is equal to 1. That tells us that we need a -4 multiplying this sin(x). So... The last option is the correct answer
do you understand?
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