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Mathematics 12 Online
OpenStudy (anonymous):

Help!!!!!!!

OpenStudy (anonymous):

Identify the number that does not belong with the other three. Explain your reasoning. 50.1 repeating 1, negative 50 over 2, negative 50.1, square root 50

OpenStudy (anonymous):

@confluxepic Help!!!!!

OpenStudy (anonymous):

@ParthKohli please help

OpenStudy (anonymous):

@whpalmer4 please help

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (anonymous):

@Michele_Laino please help

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (astrophysics):

The one that isn't rational

OpenStudy (astrophysics):

You would first assume -50/2 just because it's negative, but that is also a rational number, but one of the numbers here isn't rational...so what would the answer be?

OpenStudy (anonymous):

-50.1

OpenStudy (michele_laino):

hint: \[\Large 50.\overline 1 = \frac{{501 - 50}}{9}\]

OpenStudy (anonymous):

im confused

OpenStudy (astrophysics):

Look up the definition for rational number

OpenStudy (michele_laino):

hint: we can write this \[\Large \begin{gathered} 50.\overline 1 = \frac{{501 - 50}}{9} = \frac{{451}}{9} \hfill \\ \hfill \\ - \frac{{50}}{2},\quad - 50.1 = - \frac{{501}}{{10}} \hfill \\ \end{gathered} \]

OpenStudy (michele_laino):

furthermore, we are not able to find a pair of integer numbers, say m, and n, such that: \[\Large \sqrt 2 = \frac{m}{n}\]

OpenStudy (anonymous):

i do not understand

OpenStudy (michele_laino):

oops.. \[\Large \sqrt {50} = \frac{m}{n}\]

OpenStudy (michele_laino):

in other words, the first three numbers can be expressed as ratios, whereas the fourth number, namely sqrt(50), can not be expressed as a ratio, so what can you conclude?

OpenStudy (anonymous):

square root 50 does not belong

OpenStudy (anonymous):

but why ? @Michele_Laino

OpenStudy (michele_laino):

because sqrt(50) we can not find a pair of integers, (m,n) such that: \[\Large \sqrt {50} = \frac{m}{n}\] in other words sqrt(50) is an irrational number, whereas the others three numbers are rational numbers, since they can be expressed as fractions

OpenStudy (astrophysics):

Easily put, rational numbers are any number that can be made by dividing two integers, but \[\sqrt{50}\] can't be, same reason for pi, that is not a rational number,

OpenStudy (anonymous):

@Michele_Laino can you help me with two more

OpenStudy (michele_laino):

ok!

OpenStudy (anonymous):

Which mathematical symbol would best fill in the blank to compare the two real numbers? 7.6 repeating blank square root 55 < > = ≈

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

what do you mean with 7.6 repeating blank?

OpenStudy (anonymous):

\[7.6 ____ \sqrt{55}\]

OpenStudy (michele_laino):

do you mean 7.6?

OpenStudy (michele_laino):

if we make the square of the two numbers, we get this: \[\Large {7.6^2} = {\left( {\frac{{76}}{{10}}} \right)^2} > 55\] am I right?

OpenStudy (anonymous):

so it would be greater

OpenStudy (michele_laino):

yes! also between the starting numbers the same symbol holds

OpenStudy (anonymous):

which symbol is greater again?

OpenStudy (michele_laino):

the right symbol is: ">"

OpenStudy (michele_laino):

in general, if: \[\large {n^2} > {m^2}\] then: \[\Large n > m\]

OpenStudy (michele_laino):

where n and m are positive numbers

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Order the set of numbers from least to greatest: negative 5 over 6, negative 5, negative square root 26, negative 31 over 6 negative 31 over 6, negative square root 26, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative 31 over 6, negative square root 26 negative square root 26, negative 31 over 6, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative square root 26, negative 31 over 6

OpenStudy (michele_laino):

As before I consider the square of each number: \[\Large \begin{gathered} - \frac{5}{6} \to {\left( { - \frac{5}{6}} \right)^2} = \frac{{25}}{{36}} \hfill \\ \hfill \\ - 5 \to {\left( { - 5} \right)^2} = 25 = \frac{{900}}{{36}} \hfill \\ \hfill \\ - \sqrt {26} \to 26 = \frac{{936}}{{36}} \hfill \\ \hfill \\ - \frac{{31}}{6} \to {\left( { - \frac{{31}}{6}} \right)^2} = \frac{{961}}{{36}} \hfill \\ \end{gathered} \]

OpenStudy (anonymous):

can i say what my answer is

OpenStudy (michele_laino):

I'm sorry I can not say the answer directly, since it is against the Code of Conduct

OpenStudy (michele_laino):

please compare the square of those numbers

OpenStudy (michele_laino):

we have this drawing: |dw:1439319394062:dw|

OpenStudy (michele_laino):

am I right?

OpenStudy (michele_laino):

furthermore, you have to keep in mind that your numbers are negative, so the number which has the square bigger than others, is the first number in your sequence

OpenStudy (anonymous):

its the last answer -5/6 -5 - square 26 -31/6

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (anonymous):

least to greatest

OpenStudy (michele_laino):

no, since -31/6 has the square bigger than others, so it is the first number of your sequence, so we have: -31/6,...

OpenStudy (anonymous):

so its A

OpenStudy (michele_laino):

the order is reversed, since your numbers are all negative numbers

OpenStudy (michele_laino):

yes! correct, it is option A

OpenStudy (anonymous):

thank your Michele (:

OpenStudy (michele_laino):

:)

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