Help!!!!!!!
Identify the number that does not belong with the other three. Explain your reasoning. 50.1 repeating 1, negative 50 over 2, negative 50.1, square root 50
@confluxepic Help!!!!!
@ParthKohli please help
@whpalmer4 please help
@Michele_Laino
@Michele_Laino please help
@Michele_Laino
The one that isn't rational
You would first assume -50/2 just because it's negative, but that is also a rational number, but one of the numbers here isn't rational...so what would the answer be?
-50.1
hint: \[\Large 50.\overline 1 = \frac{{501 - 50}}{9}\]
im confused
Look up the definition for rational number
hint: we can write this \[\Large \begin{gathered} 50.\overline 1 = \frac{{501 - 50}}{9} = \frac{{451}}{9} \hfill \\ \hfill \\ - \frac{{50}}{2},\quad - 50.1 = - \frac{{501}}{{10}} \hfill \\ \end{gathered} \]
furthermore, we are not able to find a pair of integer numbers, say m, and n, such that: \[\Large \sqrt 2 = \frac{m}{n}\]
i do not understand
oops.. \[\Large \sqrt {50} = \frac{m}{n}\]
in other words, the first three numbers can be expressed as ratios, whereas the fourth number, namely sqrt(50), can not be expressed as a ratio, so what can you conclude?
square root 50 does not belong
but why ? @Michele_Laino
because sqrt(50) we can not find a pair of integers, (m,n) such that: \[\Large \sqrt {50} = \frac{m}{n}\] in other words sqrt(50) is an irrational number, whereas the others three numbers are rational numbers, since they can be expressed as fractions
Easily put, rational numbers are any number that can be made by dividing two integers, but \[\sqrt{50}\] can't be, same reason for pi, that is not a rational number,
@Michele_Laino can you help me with two more
ok!
Which mathematical symbol would best fill in the blank to compare the two real numbers? 7.6 repeating blank square root 55 < > = ≈
@Michele_Laino
what do you mean with 7.6 repeating blank?
\[7.6 ____ \sqrt{55}\]
do you mean 7.6?
if we make the square of the two numbers, we get this: \[\Large {7.6^2} = {\left( {\frac{{76}}{{10}}} \right)^2} > 55\] am I right?
so it would be greater
yes! also between the starting numbers the same symbol holds
which symbol is greater again?
the right symbol is: ">"
in general, if: \[\large {n^2} > {m^2}\] then: \[\Large n > m\]
where n and m are positive numbers
yes
Order the set of numbers from least to greatest: negative 5 over 6, negative 5, negative square root 26, negative 31 over 6 negative 31 over 6, negative square root 26, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative 31 over 6, negative square root 26 negative square root 26, negative 31 over 6, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative square root 26, negative 31 over 6
As before I consider the square of each number: \[\Large \begin{gathered} - \frac{5}{6} \to {\left( { - \frac{5}{6}} \right)^2} = \frac{{25}}{{36}} \hfill \\ \hfill \\ - 5 \to {\left( { - 5} \right)^2} = 25 = \frac{{900}}{{36}} \hfill \\ \hfill \\ - \sqrt {26} \to 26 = \frac{{936}}{{36}} \hfill \\ \hfill \\ - \frac{{31}}{6} \to {\left( { - \frac{{31}}{6}} \right)^2} = \frac{{961}}{{36}} \hfill \\ \end{gathered} \]
can i say what my answer is
I'm sorry I can not say the answer directly, since it is against the Code of Conduct
please compare the square of those numbers
we have this drawing: |dw:1439319394062:dw|
am I right?
furthermore, you have to keep in mind that your numbers are negative, so the number which has the square bigger than others, is the first number in your sequence
its the last answer -5/6 -5 - square 26 -31/6
@Michele_Laino
least to greatest
no, since -31/6 has the square bigger than others, so it is the first number of your sequence, so we have: -31/6,...
so its A
the order is reversed, since your numbers are all negative numbers
yes! correct, it is option A
thank your Michele (:
:)
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