Question

How do I solve this?

Answer 1

\[2\left| x+3 \right| = 4\] and \[(\left| y + 1 \right|) \div 3 = 2\] then \[\left| x + y \right|\] could equal all of the following EXCEPT:

(A) 0
(B) 4
(C) 8
(D) 10
(E) 12

I know the answer is 10, but why?

Answer 2

@pooja195

Answer 3

There are 2 answers to both the absolute value equations.
If you add mix the 4 answers and add them in all different ways, there would be 4 different values from absolute value of (x+y)

Answer 4

i will do x

\(2|x+3|=4\)
\(|x+3|=2\)
\(x+3=\pm 2\)
\(x = -3 \pm 2 = -5, -1\)

if you do y, you should get 2 poss values of y



pop them in here, then do | | to them, thus you will have the 4 possible outcomes