Question

nick1234567
Area of one leaf of the rose r=3sin(4theta)

Answer 1

I'm very sorry, it is 2:38 a.m. (Italy time zone) from me so I have to go to sleep

Answer 2

Please help!

Answer 3

Need answer in next 3 mins please

Answer 4

Ur the best!

Answer 5

ok any ideas on where to start?

Answer 6

Nope no clue and it's my last prob due in 3 mins

Answer 7

Can u please save me

Answer 8

http://www.wolframalpha.com/input/?i=r%3D3sin%284theta%29

Answer 9

So? Area is?

Answer 10

Only have 1min left thank u again

Answer 11

Ideas???

Answer 12

Needs suggestion in the ext 39 sec

Answer 13

Things like this cant be done in that much time. You need to make sure you have time for it

Answer 14

You will need to use
\[\huge~\rm~\int\limits_{}^{}1/2r^2d \emptyset\]

Answer 15

if this is an emergency, this is a brief attempt:

\(r=3sin(4 \theta)\)

\(r = 0, \ 4\theta = 0, \ \pi \implies \theta = 0, \pi/4, ....\)

\(A = \frac{1}{2} \int_{0}^{\pi / 4} 9 sin^2 (4 \theta) \ d \theta \)
\( = \frac{9}{4} \ \int_{0}^{\pi / 4} 1 - cos \ 8 \theta \ d \theta\)
\( = \frac{9}{4} \ [ \theta - \frac{1}{8}sin \ 8 \theta \ ]_{0}^{\pi / 4}\)
\( = \frac{9}{4} \ [ \frac{\pi}{4} ] = \frac{9 \pi}{16}\)

Answer 16

^or that works too ;p

Answer 17

You will need to use
\[\huge~\rm~\int\limits_{}^{}1/2r^2d \theta\]
\[\huge~\rm~\int\limits\limits_{\alpha }^{\beta }1/2r^2d \theta \]
\[\huge~\rm~\int\limits\limits\limits_{0 }^{\ \pi/4 }1/2(3\sin(4\theta))^2d \theta =\frac{ 9 }{ 16 }\pi \]

Answer 18

lol... why is this q orange?