Question

Identify the 42nd term of an arithmetic sequence where a1 = −12 and a27 = 66.

Answer 1

\[a_{27}=-12+26\times d=66\] solve for \(d\) first

Answer 2

So, I got a27=14xd=66

Answer 3

no

Answer 4

solve \[-12+26d=66\] first just like you solve any linear equation

Answer 5

d=3

Answer 6

add \(12\) to both sides, then divide both sides by \(26\) to solve for \(d\)

Answer 7

yeah \(d=3\)

Answer 8

Do we plug it back again?

Answer 9

so the 42 term is
\[-12+41\times 3\]

Answer 10

111?

Answer 11

idk i didn't do it
hold on

Answer 12

ok:)

Answer 13

yeah looks good