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Given log26+log29=log2X What is the value of X?
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Hint* \[\large log_c({a}) + log_c({b}) = log_c({a\times b})\]
You can use that to compress the left hand side, which will then make it very easy to see what you need to do next
Need the answer and i will fan you.
Sorry man no answers... \[\large log(26) + log(29) = log(2x)\] \[\large log(a) + log(b) = log(a\times b)\] here: a = 26 and b = 29 Use this to simplify the left, and then you will be able to solve for 'x'
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i bet it is \[\log_2(6)+\log_2(9)=\log_2(x)\] am i right?
^Hadn't considered that! Thanks for that @misty1212
Thank you!!!
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