Physics;accounting for tension of a pulley on frictionless surface.
Tension of the pulley is calculated using........
newtons laws of motion
applying newtons law to the whole system force = mass * acceleration 6*g = 11 * a a = 6*9.8 /11 = 5.35 m s-2
now i know how to find the tension in the string considering the horizontal string applying newtons second law;- Tension = 10 * 5.35 = 53. 5 N
but you require tension in the pulley right?
i think its mg= 6*9.8=tension on the string since the is no effect of 5 kg wt. as surface is frictionless
sorry i dont know where i got 10 from!!!!
if you consider the horizontal string its 5 * 5.35 not 10 * 5.35
hhmm.. i'm not sure I would have thought you would have to take the 5 kg into account. Its been a long time since i did these...
@welshfella how can you add 6+5= 11 to get 11*a this is not the case actually...
but i'mm considering the whole system 5 kg and 6 kg are part of the whole system
6 g is the downward force (dues to 6 kg mass) but 5kg is part of the mass
the tension will be the same throughout the whole string so i guess thats also the force on the pulley
5kg would have created friction on the surface due to wt. which would hav then created a resistance to allow the whole system to move down....this would hav decreased the tension on the string but here the surface is frictionless...
hmm maybe but i dont think you can ignore the 5 kg...
maybe i'm wrong
I'd have to look it up
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