Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (lifeisadangerousgame):

Can anyone give me an explanation for this? http://cdn2.hubspot.net/hub/360031/hubfs/body_arithmetic-1.jpg?t=1439394385622&width=504

ganeshie8 (ganeshie8):

\(n^2\ge 1\tag{1}\) \(\implies |n| \ge 1\) \( \implies n^2\ge n\tag{2}\) adding both equations yields \(n^2+n^2\ge 1+n\) \(\implies 2n^2-n\ge 1\)

OpenStudy (lifeisadangerousgame):

Would testing each answer out work as well? I tried, but it didn't work out for me. Memorizing isn't my strong point, so I'm trying to figure out other methods.

Nnesha (nnesha):

i would do that.^^^^ :P

Nnesha (nnesha):

i'll pick a number for n let n=-6 \[2(-6)^3+(-6)=2(-216)-6=-438\] so \[\ \cancel{E}\] \[(-6)^3 +(-6) = -216-6 =-222\] D isn't correct \[\ \cancel{D}\] \[(-6)^2+(-6)^3 = 36-216=-180\] \[\ \cancel{C}\] now there are 2 possible options hmmm\[\rm 2(-6)^2-(-6) ~and~(-6)^2-6\]

OpenStudy (lifeisadangerousgame):

they both end up positive?

Nnesha (nnesha):

yeah...

OpenStudy (lifeisadangerousgame):

so how do I know which one is correct?

Nnesha (nnesha):

\[\rm 2(-6)^2-(-6) ~and~(-6)^2-6\] \[2(36)\color{reD}{+}6 ~~~~~~~~~~~~~~~~~~~ 36\color{reD}{-}6\] hmmm i guess ^^addition ^subtraction different signs hmm LOL sometimes i use my own method *sigh*

Nnesha (nnesha):

anyway i'll work on this later i'm sleepy rn....

OpenStudy (lifeisadangerousgame):

oh okay, thanks for your help!

Nnesha (nnesha):

np :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!