Question

Physics proof read for a question;A block whose mass is 6.0 kg sits on a level floor. The coefficient of static friction between the block and the floor is 0.42. What horizontal force is required to make the block move?

Answer 1

My answer;Given that coefficient of static friction=0.42
Mass of the block=6.0kg
Gravity=9.8m/s^2


The horizontal force required to make the block move is calculated as follows,


Fmg = (6.0kg)(9.8m/s^2)=58.8N

Given the coefficient of static friction which is 0.42

58.8N*4.2=24.696N

Given the sig figs of 2,

The force required to move the block is 25N

Answer 2

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Answer 3

Awesome