If\( F (x,y) =
The net is so bad so that I am on and off. Please, leave the guidance, I will be back right after I can access to the net.
for the first part, it's worth checking the field is [strictly, might be] conservative by checking out \( curl \ \vec F = 0\), which it is then, as you know that \(\large f_x = e^{2y}\) and \(\large f_y = 1+2xe^{2y} \), you solve the DE's remembering that the constant of integration for the first one will be some function of y, and vice versa for the second
\[\frac{d \vec r}{dt}=\frac{dx}{dt}\hat i+\frac{dy}{dt}\hat j\] \[\implies d \vec r=dx \hat i+dy \hat j\] \[\therefore \vec F. d \vec r=F_{x}dx+F_{y}dy\]
or for 1) as this is conservative, you can integrate along a convenient path, eg (0,0) to (0,y) to (x,y). |dw:1439405196704:dw|
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