Question

If a factory continuously pumps pollutants into the air at the rate of the quotient of the square root of t and 15 tons per day, then the amount dumped after 3 days is

Answer 1

\[\frac{ \sqrt{t} }{ 15 }\]

Answer 2

@IrishBoy123 @triciaal

Answer 3

u need me bro

Answer 4

umm yeah

Answer 5

wait was that a question or a statement ?

Answer 6

it is 45 tons in three days

Answer 7

sorry its 6.708203932

Answer 8

Medal plzzzzzzzzzzzzzzzzzzzzzz

Answer 9

\(\large \frac{dP}{dt} = \frac{\sqrt{t}}{15} \)

\(\large P(3) = \frac{1}{15} \ \int_{t=0}^{3} \sqrt{t} \ dt = \frac{1}{15} | \frac{2}{3}.t^{3/2}|_{t=0}^{3} = \frac{2}{45}. \sqrt{27} =\frac{2 \sqrt{3}}{15} = 0.231\)

Answer 10

what

Answer 11

now im confused

Answer 12

@watchpencilpaper

is this what you were expecting?

did you have a method in mind for solving this?

Answer 13

yes

Answer 14

i

Answer 15

did

Answer 16

have

Answer 17

a

Answer 18

method

Answer 19

no i had no method in mind and it appears you are right @IrishBoy123

Answer 20

@watchpencilpaper

so how were you going to solve this -- without using calculus?!?!

Answer 21

@Napolions
your method please!! please share it.

Answer 22

what do you mean, i intended to say i did not know how to solve it, obviously you need calculus

Answer 23

ok

@Napolions

please, is there a cooler way to do this? do share.

Answer 24

naw but there was a website that helped me