Create one trinomial function: f(x) = x^3 - 3x^2 - x + 3., and a linear function g(x) = (x - 1).
Part 1. Divide f(x) by g(x). You must do it yourself using the long division you have learned
f(x)/g(x) = (x^3 - 3x^2 + x + 3)/(x - 1) = x^2 - 2x + 3 (no remainder)
Part 2: a = 1 -> f(a) = f(1) = 0
Part 3. Use the remainder theorem?
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OpenStudy (anonymous):
do this help
OpenStudy (anonymous):
The Remainder Theorem starts with an unnamed polynomial p(x), where "p(x)" just means "some polynomial p whose variable is x". Then the Theorem talks about dividing that polynomial by some linear factor x – a, where a is just some number. Then, as a result of the long polynomial division, you end up with some polynomial answer q(x) (the "q" standing for "the quotient polynomial") and some polynomial remainder r(x).
this is the defonition
OpenStudy (anonymous):
@plzzhelpme
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
@Napolions
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
draw it out for me
OpenStudy (anonymous):
what would it mean
OpenStudy (anonymous):
and you are correct
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