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OpenStudy (anonymous):
@calculusxy
OpenStudy (anonymous):
@Vocaloid
OpenStudy (anonymous):
@Nnesha
OpenStudy (anonymous):
@peachpi
OpenStudy (astrophysics):
\[2\sqrt{5(105)}?\]
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OpenStudy (anonymous):
Yes @Astrophysics
OpenStudy (astrophysics):
Ok so what have you tried?
OpenStudy (anonymous):
I don't know how to solve big square roots really. But I need this now :( @Astrophysics
OpenStudy (astrophysics):
\[2\sqrt{525}\] maybe that's easier, just keep simplifying that
OpenStudy (anonymous):
Okay I got 10 times sqrt21 @Astrophysics
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OpenStudy (astrophysics):
Yes! Exactly
OpenStudy (anonymous):
That's the answer ?
OpenStudy (astrophysics):
Yup :)
OpenStudy (anonymous):
Okay well I'm solving this problem LAW ENFORCEMENT: A police accident investigator can use the formula S25L to estimate the speed s of a car in miles per hour based on the length l in feet of the skid marks it left. How fast was a car traveling that left skid marks 105 feet long? And I have to round the answer to the nearest mph @ Astrophysics
OpenStudy (anonymous):
@Astrophysics
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OpenStudy (astrophysics):
What is S25L
OpenStudy (anonymous):
S=2sqrt5l
OpenStudy (astrophysics):
Oooh \[S = 2\sqrt{5L}\]
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
I need this answer in the next 3 minutes :(
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OpenStudy (astrophysics):
So S is your speed and L is your length this is exactly the same as your problem above
OpenStudy (astrophysics):
plug L = 105
OpenStudy (astrophysics):
I guess you don't have to convert any units either ft into miles or what ever does look like it
OpenStudy (anonymous):
so that's the answer 10 times sqrt ?
OpenStudy (anonymous):
Sqrt21 ? So there is no rounding to the nearest mph
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OpenStudy (astrophysics):
Then put it in decimals if it's asking in that
OpenStudy (anonymous):
What would it be
OpenStudy (astrophysics):
Use a calculator..
OpenStudy (anonymous):
One minute left :(
OpenStudy (astrophysics):
I got 46
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