Question

PHYSICS!!! YAY

Answer 1

there is friction between the 5.00 kg block and tabletop. The coefficient of kinetic friction is 0.25.

Answer 2

So this is a pulley problem. Identifying the acceleration of the whole system given the kinetic friction force amounting to 0.25;)

Answer 3

So far what I've got is the force acting due to gravity on 5.0kg object which is (5kg)(9.8N/kg)=49N

Answer 4

And force acting on the 6.0kg object which is (6.0kg)(9.8m/s^2)=58.8N

Answer 5

The thing is force acting on the 5.0kg is horizontal hence not overly responsible for the Fmg had by 5.0kg itself.

Answer 6

Given the kinetic energy of 0.25 I believe that 25% of force once it starts to move is lost to thermal energy.

Answer 7

Therefore my reasoning is that 5.0kg object is pulled to the right horizontally by a force of 58.8N-58.8*0.25

Answer 8

58.8N-14.7N=44.1N

Answer 9

Given the force acting to the right of 5.00 kg object, using the equation F=ma
44.1N=(5.00kg)a a=8.82m/s^2

Answer 10

What do you think @IrishBoy123

Answer 11

you need to draw these first, free body diagrams, then you can solve in a jiffy :p