How can I integrate this
X^2+2xy-y^2/(x+y)^2
(X^2+2xy-y^2/(x+y)^2)dx
please take a screenshot of complete problem and post
\[\frac{ (x ^{2}+2xy-y ^{2}) }{ (x+y)^2 } dx\]
integrate pls
sir @ganeshie8
is this part of an iterated integral (double integral) ?
Im just answering an exact differential equation and the last part to find my equation is to integrate that.
y are consider as constant
y are consider as a constant
@ganeshie8
I would probably write it like this: \[\int\limits_{}^{}(1-\frac{2y^2}{(x+y)^2}) dx\] then evaluate
notice: \[\frac{x^2+2xy-y^2}{(x+y)^2}=\frac{x^2+2xy+y^2 -2y^2}{(x+y)^2}=\frac{(x+y)^2-2y^2}{(x+y)^2}\]
I already got that I use long division
u=x+y then du=dx
\[\int\limits_{}^{}1 dx-2y^2 \int\limits \frac{1}{(x+y)^2} dx\]
Hey @EinsteinMorse if you're solving an exact differential equation, you cannot integrate it like this x and y are dependent
yeeaah thanks . I wanted to confirm my answwer
`y are consider as constant` how do you know ?
I already got the same idea like what've frekles told . I just want confirmation on that.
y is constant because it is dx
may i know the starting differential equaiton ?
I'm asking because I feel that you're doing it wrong.. your goal in solving a differential equation is to find the curve \(y\), it is not constant, it is a function of x.
Join our real-time social learning platform and learn together with your friends!