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Mathematics 13 Online
OpenStudy (anonymous):

How can I integrate this

OpenStudy (anonymous):

X^2+2xy-y^2/(x+y)^2

OpenStudy (anonymous):

(X^2+2xy-y^2/(x+y)^2)dx

ganeshie8 (ganeshie8):

please take a screenshot of complete problem and post

OpenStudy (anonymous):

\[\frac{ (x ^{2}+2xy-y ^{2}) }{ (x+y)^2 } dx\]

OpenStudy (anonymous):

integrate pls

OpenStudy (anonymous):

sir @ganeshie8

ganeshie8 (ganeshie8):

is this part of an iterated integral (double integral) ?

OpenStudy (anonymous):

Im just answering an exact differential equation and the last part to find my equation is to integrate that.

OpenStudy (anonymous):

y are consider as constant

OpenStudy (anonymous):

y are consider as a constant

OpenStudy (anonymous):

@ganeshie8

OpenStudy (freckles):

I would probably write it like this: \[\int\limits_{}^{}(1-\frac{2y^2}{(x+y)^2}) dx\] then evaluate

OpenStudy (freckles):

notice: \[\frac{x^2+2xy-y^2}{(x+y)^2}=\frac{x^2+2xy+y^2 -2y^2}{(x+y)^2}=\frac{(x+y)^2-2y^2}{(x+y)^2}\]

OpenStudy (anonymous):

I already got that I use long division

OpenStudy (freckles):

u=x+y then du=dx

OpenStudy (freckles):

\[\int\limits_{}^{}1 dx-2y^2 \int\limits \frac{1}{(x+y)^2} dx\]

ganeshie8 (ganeshie8):

Hey @EinsteinMorse if you're solving an exact differential equation, you cannot integrate it like this x and y are dependent

OpenStudy (anonymous):

yeeaah thanks . I wanted to confirm my answwer

ganeshie8 (ganeshie8):

`y are consider as constant` how do you know ?

OpenStudy (anonymous):

I already got the same idea like what've frekles told . I just want confirmation on that.

OpenStudy (anonymous):

y is constant because it is dx

ganeshie8 (ganeshie8):

may i know the starting differential equaiton ?

ganeshie8 (ganeshie8):

I'm asking because I feel that you're doing it wrong.. your goal in solving a differential equation is to find the curve \(y\), it is not constant, it is a function of x.

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