Question

Please explain how to find the value for k for which this equation has one repeated root x^2-2x+k=0

Answer 1

why no start with seeing what it looks like to have a repeated root, say a?

so multiply out \((x-a)^2\) and pattern match

Answer 2

(x-a)(x-a)
x^2-ax-ax+a^2

I don't quite understand how this relates to the problem?

Answer 3

\(x^2-ax-ax+a^2 = \\ x^2 - 2ax + a^2\)


original problem:
\(x^2-2x+k=0\)

geddit?

Answer 4

Sorry, no I really don't. The two equations don't look similar to me because the original equation does not have two squared variables and the middle term doesn't have two variables.

Answer 5

pattern match