Please explain how to find the value for k for which this equation has one repeated root x^2-2x+k=0

Question

irishboy123 · Answer

why no start with seeing what it looks like to have a repeated root, say a?

so multiply out $(x-a)^2$ and pattern match

anonymous · Answer

(x-a)(x-a)
x^2-ax-ax+a^2

I don't quite understand how this relates to the problem?

irishboy123 · Answer

$x^2-ax-ax+a^2 = \ x^2 - 2ax + a^2$


original problem:
$x^2-2x+k=0$

geddit?

anonymous · Answer

Sorry, no I really don't. The two equations don't look similar to me because the original equation does not have two squared variables and the middle term doesn't have two variables.

irishboy123 · Answer

pattern match

irishboy123 · Answer

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