In the following triangle, = 60. Find the values of the angles B and B', which solve this ambiguous case
http://media.apexlearning.com/Images/200801/09/cf213ca3-b382-45ab-ac52-d2473fc03d56.gif

A. B = 56.8 or B' = 123.2
B. B = 64.13 or B' = 115.87
C. B = 62.56 or B' = 117.44
D. B = 62.03 or B' = 117.97

Question

In the following triangle,  = 60. Find the values of the angles B and B', which solve this ambiguous case
http://media.apexlearning.com/Images/200801/09/cf213ca3-b382-45ab-ac52-d2473fc03d56.gif


 		A.	B = 56.8 or B' = 123.2
 		B.	B = 64.13 or B' = 115.87
 		C.	B = 62.56 or B' = 117.44
 		D.	B = 62.03 or B' = 117.97

mathstudent55 · Answer

Use the law of sines first.

anonymous · Answer

i could really use the help going thru this

anonymous · Answer

i think its is B.

mathstudent55 · Answer

I have no idea what the answer is. First use the law of cosines to find angle B or B'.

$\large \dfrac{15.4}{\sin 60^o} = \dfrac{16}{\sin B'}$

Use this to find B'.

Then we'll continue.