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OpenStudy (mathmath333):

Probablity Question

OpenStudy (mathmath333):

Check whether the following probabilities P(A) and P(B) are consistently defined (i) P(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0.6 (ii) P(A) = 0.5, P(B) = 0.4, P(A ∪ B) = 0.8

OpenStudy (mathmath333):

i found an answer here but it doesn't making sense to me http://www.meritnation.com/ask-answer/question/check-whether-the-following-probabilities-p-a-and-p-b-are/probability/6322947

Vocaloid (vocaloid):

in order to be consistently defined: P(A ∩ B) must be less than or equal to P(A) and P(B) P(A ∪ B) must be greater than or equal to P(A) and P(B)

OpenStudy (mathmath333):

u mean both conditions or any one condition should be satisfied

Vocaloid (vocaloid):

both

Vocaloid (vocaloid):

so, for the first one (i) what do you think the answer is? (i) P(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0.6

OpenStudy (mathmath333):

consistentlyt defined

Vocaloid (vocaloid):

not quite, check the first condition again... P(A ∩ B) must be less than or equal to P(A) and P(B)

Vocaloid (vocaloid):

notice how P(A ∩ B) is greater than P(B)?

OpenStudy (zarkon):

these "P(A ∩ B) must be less than or equal to P(A) and P(B) P(A ∪ B) must be greater than or equal to P(A) and P(B)" are necessary conditions but not sufficient

OpenStudy (mathmath333):

i am confused

OpenStudy (anonymous):

|dw:1439556261906:dw|

OpenStudy (anonymous):

The second one is possible, since they can overlap 0.2 to get A U B = 0.8 |dw:1439556485375:dw|

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