Question

3^(x^2+5x+32)=81^(3-x)

Answer 1

I don't understand @OOOPS

Answer 2

do you divide (x^2+5x+32) by 3-x?

Answer 3

well your question wasnt really clear

Answer 4

\(\Large 3^{x^2+5x+32}=81^{3-x}\)

\(\Large 3^{x^2+5x+32}=(3^4)^{3-x}\)

\(\Large 3^{x^2+5x+32}=3^{12-4x}\)

\(\Large x^2+5x+32=12-4x\)

Solve the quadratic above.

Answer 5

@mathstudent55 would i make it into 0?

Answer 6

HI!!

Answer 7

hello!

Answer 8

\[x^2+5x+32=12-4x\] is what you have to solve right?

Answer 9

add \(4x\) and subtract \(12\) to get
\[x^2+9x+20=0\]

Answer 10

fortunately for you this one factors so it is easy to solve

Answer 11

i got (x+5)(x+4)
so i then equal it to 0 to find x?

Answer 12

@misty1212

Answer 13

yes

Answer 14

you can probably do it in your head

Answer 15

so its -5 and -4

Answer 16

oui

Answer 17

\[\color\magenta\heartsuit\]

Answer 18

thank you so much!!!

Answer 19

you are welcome dear