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Mathematics 21 Online
OpenStudy (anonymous):

What are the foci of the following graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

What are the vertices?

OpenStudy (anonymous):

3 and -3?

OpenStudy (anonymous):

that are co-vertex, how about main one?

OpenStudy (anonymous):

5 and -5

OpenStudy (anonymous):

i ment 6 and -6

OpenStudy (anonymous):

ok, it is a vertical ellipse, hence the main one is a, and the co- one is b that is a = 6 and b =3 you have the formula to find foci c, which is \(c^2 = a^2 -b^2\), hence c =??

OpenStudy (anonymous):

27?

OpenStudy (anonymous):

that is c^2 , not c

OpenStudy (anonymous):

13.5?

OpenStudy (anonymous):

\(\sqrt{27} =??\)

OpenStudy (anonymous):

5.19615

OpenStudy (anonymous):

ok, it is \(3\sqrt3\) you can take your number.

OpenStudy (anonymous):

One more thing, foci are on the same line with main vertices, right? your main one is \((0, \pm 6)\), hence your foci are \((0,\pm 3\sqrt3)\) Whenever jot down the foci or the vertex, you MUST write the pair of them to make it clear for the shape of the conic.

OpenStudy (anonymous):

so what the anwser? im sorry..this confuesses me

OpenStudy (anonymous):

@OOOPS

OpenStudy (anonymous):

@Peaches15

OpenStudy (anonymous):

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