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Mathematics 24 Online
OpenStudy (anonymous):

What is the equation of the following graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

@OOOPS help again? you seem to be the only one who can solve these and show me how to do it. please?

OpenStudy (anonymous):

@nincompoop

OpenStudy (anonymous):

@LynFran

OpenStudy (anonymous):

@Peaches15

OpenStudy (anonymous):

what is the center of the ellipse?

OpenStudy (anonymous):

(2,2)

OpenStudy (anonymous):

What is the standard form of a SHIFTED-VERTICAL ellipse?

OpenStudy (anonymous):

i honestly dont know...

OpenStudy (anonymous):

google or look up at your book.

OpenStudy (anonymous):

(x-h)^2/b^2 + (y-v)^2/a^2=1

OpenStudy (anonymous):

so h and k are both 2? since 2,2 is the center

OpenStudy (anonymous):

Print it out for you to look up the information later.

OpenStudy (anonymous):

\(\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\)

OpenStudy (anonymous):

Look at the MAIN vertices, what is a?

OpenStudy (anonymous):

-1?

OpenStudy (anonymous):

|dw:1439516548747:dw|

OpenStudy (anonymous):

This is kind of trick, but it works well. The distance between the 2 Main vertices is 6, right?

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

hence a = 6/2 =3

OpenStudy (anonymous):

same as b, with the co-vertices.

OpenStudy (anonymous):

|dw:1439516691048:dw|

OpenStudy (anonymous):

b=2

OpenStudy (anonymous):

|dw:1439516711884:dw|

OpenStudy (anonymous):

Yes, now, plug them in, what do you get?

OpenStudy (anonymous):

|dw:1439516756234:dw|

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