Mathematics
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OpenStudy (anonymous):
What is the equation of the following graph?
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OpenStudy (anonymous):
OpenStudy (anonymous):
@OOOPS help again? you seem to be the only one who can solve these and show me how to do it. please?
OpenStudy (anonymous):
@nincompoop
OpenStudy (anonymous):
@LynFran
OpenStudy (anonymous):
@Peaches15
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OpenStudy (anonymous):
what is the center of the ellipse?
OpenStudy (anonymous):
(2,2)
OpenStudy (anonymous):
What is the standard form of a SHIFTED-VERTICAL ellipse?
OpenStudy (anonymous):
i honestly dont know...
OpenStudy (anonymous):
google or look up at your book.
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OpenStudy (anonymous):
(x-h)^2/b^2 + (y-v)^2/a^2=1
OpenStudy (anonymous):
so h and k are both 2? since 2,2 is the center
OpenStudy (anonymous):
Print it out for you to look up the information later.
OpenStudy (anonymous):
\(\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\)
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OpenStudy (anonymous):
Look at the MAIN vertices, what is a?
OpenStudy (anonymous):
-1?
OpenStudy (anonymous):
|dw:1439516548747:dw|
OpenStudy (anonymous):
This is kind of trick, but it works well.
The distance between the 2 Main vertices is 6, right?
OpenStudy (anonymous):
yes?
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OpenStudy (anonymous):
hence a = 6/2 =3
OpenStudy (anonymous):
same as b, with the co-vertices.
OpenStudy (anonymous):
|dw:1439516691048:dw|
OpenStudy (anonymous):
b=2
OpenStudy (anonymous):
|dw:1439516711884:dw|
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OpenStudy (anonymous):
Yes, now, plug them in, what do you get?
OpenStudy (anonymous):
|dw:1439516756234:dw|