Guys I give medals help me
find the y' of y=cos(x+y)
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OpenStudy (anonymous):
chain rule again for this one, in the guess of "implicit diff"
OpenStudy (anonymous):
think of it as
\[f(x)=\cos(x+f(x))\]
OpenStudy (anonymous):
then via the chain rule you get
\[f'(x)=-\sin(x+f(x))\times \left(1+f'(x)\right)\] solve this equation for \(f'(x)\)
OpenStudy (anonymous):
of course it is easier to write
\[y'=-\sin(x+y)(1+y')\] and solve for \(y'\)
OpenStudy (anonymous):
yeah, can I divide the y'+1 from one side to the other?
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OpenStudy (anonymous):
ok I got it
OpenStudy (anonymous):
i will leave the algebra to you , but no, that is not how you solve
you need to distribute first
OpenStudy (anonymous):
I got
|dw:1439515086039:dw|
OpenStudy (anonymous):
i just remembered my algebra stuff.. thank you again
OpenStudy (anonymous):
looks good to me
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OpenStudy (anonymous):
yeah just because you are taking calc doesn't mean the algebra has changed any
if my experience algebra is the biggest pitfall, not the ideas of calculus