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Mathematics 7 Online
OpenStudy (anonymous):

Guys I give medals help me find the y' of y=cos(x+y)

OpenStudy (anonymous):

chain rule again for this one, in the guess of "implicit diff"

OpenStudy (anonymous):

think of it as \[f(x)=\cos(x+f(x))\]

OpenStudy (anonymous):

then via the chain rule you get \[f'(x)=-\sin(x+f(x))\times \left(1+f'(x)\right)\] solve this equation for \(f'(x)\)

OpenStudy (anonymous):

of course it is easier to write \[y'=-\sin(x+y)(1+y')\] and solve for \(y'\)

OpenStudy (anonymous):

yeah, can I divide the y'+1 from one side to the other?

OpenStudy (anonymous):

ok I got it

OpenStudy (anonymous):

i will leave the algebra to you , but no, that is not how you solve you need to distribute first

OpenStudy (anonymous):

I got |dw:1439515086039:dw|

OpenStudy (anonymous):

i just remembered my algebra stuff.. thank you again

OpenStudy (anonymous):

looks good to me

OpenStudy (anonymous):

yeah just because you are taking calc doesn't mean the algebra has changed any if my experience algebra is the biggest pitfall, not the ideas of calculus

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