Guys I give medals help me
find the y' of y=cos(x+y)

Question

Guys I give medals help me 
find the y' of y=cos(x+y)

anonymous · Answer

chain rule again for this one, in the guess of "implicit diff"

anonymous · Answer

think of it as 
$$f(x)=\cos(x+f(x))$$

anonymous · Answer

then via the chain rule you get 
$$f'(x)=-\sin(x+f(x))\times \left(1+f'(x)\right)$$ solve this equation for $f'(x)$

anonymous · Answer

of course it is easier to write 
$$y'=-\sin(x+y)(1+y')$$ and solve for $y'$

anonymous · Answer

yeah, can I divide the y'+1 from one side to the other?

anonymous · Answer

ok I got it

anonymous · Answer

i will leave the algebra to you , but no, that is not how you solve
you need to distribute first

anonymous · Answer

I got 
|dw:1439515086039:dw|

anonymous · Answer

i just remembered my algebra stuff.. thank you again

anonymous · Answer

looks good to me

anonymous · Answer

yeah just because you are taking calc doesn't mean the algebra has changed any 
if my experience algebra is the biggest pitfall, not the ideas of calculus