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Solve the following system of equations.

-3x + 4y = 80
x + 4y = 32

A. x = 2, y = 21.5
B. x = 11, y = -12
C. x = 8, y = 6
D. x = -12, y = 11

Question

Fan and medal for easy problem 
check below :)

Solve the following system of equations.

-3x + 4y =	80
    x + 4y =	32

A. x = 2, y = 21.5
  B. x = 11, y = -12
  C. x = 8, y = 6
  D. x = -12, y = 11

jadedinsomniac · Answer

i got this hold up

anonymous · Answer

$$-3x+4y=80, x+4y=32$$
multiplying the second equation by (-1) we get
$$-3x+4y=80, -x-4y=-32$$
now, we sum both equations getting
$$-4x=48 \rightarrow x=-12$$
and replacing x=-12 in the first equation we get
$$-3(-12)+4y=80 \rightarrow 36+4y=80 \rightarrow 4y=44 \rightarrow y=11$$
so x=-12 and y=11 is the solution to the system of equations