another problem i'm having trouble with Show that the function F of x equals the integral from x to 4 times x of 1 over t dt is constant on the interval (0, +∞)
this is the function
not really sure where to start on this one
Hmmm well maybe you could take its derivative, and since the derivative of a constant is 0, if its derivative is 0 then you know it was a constant.
okay so then \[\frac{ 1 }{ 4x} - 1/x\]
no wait that cant be right
\[((\frac{ 1 }{ 4x })(4)) - (\frac{ 1 }{ x })\]
\[ \frac{ 4 }{ 4x} - \frac{ 1 }{ x }\]
the 4 cancel out and we end up with zero , and zero is a constant thus the function is constant .... does that seem right to you?
Yeah perfect!
YAY!!
Well not quite because zero is a constant slight note
thanks man !
zero is the derivative of a constant!
okay that makes sense , yea ... ZERO IS THE DERIVATIVE OF A CONSTANT !!
Haha yeah so you got zero for your derivative, booooom done! :P
boom indeed
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