Question

Pre-calc help? Check my answer?

Find the center, vertices, and foci of the ellipse with equation 3x^2 + 6y^2 = 18

A. Center: (0, 0); Vertices: (0,-sqrt6),(0,sqrt6); Foci: (0,-sqrt3),(0,sqrt3)
B. Center: (0, 0); Vertices: (-sqrt6,0),(sqrt6,0); Foci: (-sqrt3,0),(sqrt3,0)
C. Center: (0, 0); Vertices: (-6, 0), (6, 0); Foci: (-3*sqrt3,0),(3*sqrt3,0)
D. Center: (0, 0); Vertices: (0, -6), (0, 6); Foci: (0,-3*sqrt3),(0,3*sqrt3)

I got A as my answer. Am I correct?

Answer 1

3x^2 + 6y^2 = 18
\[\frac{ 3x^2 }{ 18 }+\frac{ 6y^2 }{ 18 }=1\]\[\frac{ x^2 }{ 6 }+\frac{ y^2 }{ 3 }=1\]
so center is (0,0)
\[a=\sqrt{6}\]\[b=\sqrt{3}\]

Answer 2

so the answer is B.

Answer 3

Oh, alright. Thank you very much for your help!