Question

Aluminum metal reacts with Iron(III) oxide to produce Iron metal and Aluminum oxide.

What mass (in grams) of Aluminum metal will react with 1.50E2 g of Iron(III) oxide?

Answer 1

@hartnn @texaschic101

Answer 2

@Nnesha @sammixboo @UsukiDoll @Jack1

Answer 3

\[Fe _{2}O _{3}+2Al \rightarrow Al _{2} O3+2Fe\]

Answer 4

so you wrote the formula and balanced it.

the next step required is to convert the mass given to moles.

after, use a molar ratio - of the moles and coefficients of each species:

\(\sf \dfrac{moles~of~A}{A's~coefficient}=\dfrac{moles~of~B}{B's~coefficient}\)

solve for moles of Al.

Convert moles to mass.

Answer 5

What are the moles of each substance @aaronq ?

Answer 6

The problem tells you the mass of Fe2O3, convert that to moles.

The moles of Al are unknown, so you will be solving for them - they would be your "x"

Answer 7

(1.50E2gFe2O3 * 1 mol) / 159.69 g Fe2O3 = 0.939 mol Fe2O3

Answer 8

(0.939 mol Fe2O3 * 2 mol Al) / 1 mol Fe203 = 1.878 mol Al

Answer 9

1.878 mol Al *26.981g Al / 1 mol Al = 50.67g Al

Answer 10

Would 50.8 be correct considering sig figs?

Answer 11

50.7 g, no?

Answer 12

sorry. so 50.7 is correct?

Answer 13

yes, it should be