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I am thinking
start from the inside and work your way out j(2) = ?
right, so h(j(2)) = ?
I helped someone with this same exact problem a couple days ago.
h(j(2)) = h(-4) = ?
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use whatever is inside the parentheses...
remember what you did for j(2)? h(-4) is just the same rule
I prefer to find h[j(x)] first
I don't want to take over. I just wanted to offer a different perspective. @Vocaloid finish explaining your approach.
alright then...
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ok, so h(j(2)) means find j(2), and use j(2) as the x value in h(x)
-13 this answer
j(2) = -4, so h(j(2)) = h(-4)
h(-4) = ?
nope, not -7 or -11... x = -4 h(x) = 3x - 1?
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lol
i am sure about my answer mate
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