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Mathematics 22 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

I am thinking

Vocaloid (vocaloid):

start from the inside and work your way out j(2) = ?

Vocaloid (vocaloid):

right, so h(j(2)) = ?

hero (hero):

I helped someone with this same exact problem a couple days ago.

Vocaloid (vocaloid):

h(j(2)) = h(-4) = ?

Vocaloid (vocaloid):

use whatever is inside the parentheses...

Vocaloid (vocaloid):

remember what you did for j(2)? h(-4) is just the same rule

hero (hero):

I prefer to find h[j(x)] first

hero (hero):

I don't want to take over. I just wanted to offer a different perspective. @Vocaloid finish explaining your approach.

Vocaloid (vocaloid):

alright then...

Vocaloid (vocaloid):

ok, so h(j(2)) means find j(2), and use j(2) as the x value in h(x)

OpenStudy (dinamix):

-13 this answer

Vocaloid (vocaloid):

j(2) = -4, so h(j(2)) = h(-4)

Vocaloid (vocaloid):

h(-4) = ?

Vocaloid (vocaloid):

nope, not -7 or -11... x = -4 h(x) = 3x - 1?

OpenStudy (dinamix):

lol

OpenStudy (dinamix):

i am sure about my answer mate

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