Question

help

Answer 1

Jack uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below:


Number on the Cube Number of Times Rolled
1 16
2 14
3 5
4 17
5 21
6 27


Heads Tails
41 59


Using Jack's simulation, what is the probability of rolling a 6 on the number cube and the coin landing on heads?
fraction 1,107 over 10,000
fraction 1,593 over 10,000
fraction 27 over 100
fraction 41 over 100

Answer 2

@Michele_Laino

Answer 3

here we have two independent events, namely the flipping of a coin and the rolling of a six-sided cube.
The probability to get a six, is:
p1=favorable outcomes / possible outcomes=
=27/(16+14+5+17+21+27)=...?

the probability to get a head is:
p2=favorable outcomes/ possible outcomes= 41/(41+59)=...?

Answer 4

60

Answer 5

what is 60?

Answer 6

please you have to compute p1 and p2

Answer 7

95.6875

Answer 8

\[\Large \begin{gathered}
{p_1} = \frac{{27}}{{16 + 14 + 5 + 17 + 21 + 27}} = ...? \hfill \\
\hfill \\
{p_2} = \frac{{41}}{{41 + 59}} = ...? \hfill \\
\end{gathered} \]

Answer 9

so D

Answer 10

I'm sorry, option D is incorrect!

Answer 11

oh wait sorry its c

Answer 12

please check my computation:
\[\Large \begin{gathered}
{p_1} = \frac{{27}}{{16 + 14 + 5 + 17 + 21 + 27}} = \frac{{27}}{{100}} \hfill \\
\hfill \\
{p_2} = \frac{{41}}{{41 + 59}} = \frac{{41}}{{100}} \hfill \\
\end{gathered} \]
am I right?

Answer 13

yes so its C

Answer 14

now, since those two ebents are independent events, then the requested probability is given by the subsequent product:
\[\Large {p_1} \cdot {p_2} = \frac{{27}}{{100}} \cdot \frac{{41}}{{100}} = ...?\]

Answer 15

events*

Answer 16

A

Answer 17

that's right!