Question

Check this.? Im not very good with logarithms and i watched a video and it said to do it like this but im not sure

Log\/2(3)+log\/2(x)=3
then cancel out the logs as they are the same base so,
3+x=3
-3 -3
x=0???

Answer 1

what's the original question ?

Answer 2

Log\/2(3)+log\/2(x)=3

Answer 3

i mean equation \[\log_2(3)+\log_2 x=3\] like this OR

Answer 4

\[\frac{ \log_2 3 }{ \log_2 x} =3\]

Answer 5

maybe or maybe division hmm
which one is correct ? graysongraddyLOL

Answer 6

the first one is the original

Answer 7

oh okay familiar with the log properties ??

Answer 8

Not exactly.

Answer 9

quotient rule\[\large\rm log_b x - \log_b y = \log_b \frac{ x }{ y}\]
to condense you can change subtraction to division
product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition ----> multiplication

power rule \[\large\rm log_b x^y = y \log_b x\]

Answer 10

look at that and tell me which one you should apply ?

Answer 11

The last one.?

Answer 12

Math just absolutely dumbfounds me.

Answer 13

hmm alright there is PLUS sign between log
now look at the log identities

Answer 14

the subexponent of 2 is the identity correct.?

Answer 15

2 is base

Answer 16

quotient rule\[\large\rm\color{reD}{ log_b x - \log_b y = \log_b \frac{ x }{ y}}\]
to condense you can change subtraction to division
product rule \[\large\rm \color{reD}{log_b x + \log_b y = \log_b( x \times y )}\]
addition ----> multiplication

power rule \[\large\rm \color{Red}{log_b x^y = y \log_b x}\]
you don't need ^power rule for this e quation
we should apply it when there is a number at front of log

Answer 17

so with the equation that i am using, How do i get a Log on the other side of the equal sign.?

Answer 18

alright we need to apply product rule which is \[\large\rm \color{reD}{log_b x + \log_b y = \log_b( x \times y )}\]

log_b same base so take it out and multiply x y
\[\log_b x+ \log_b y\]
\[\log_b (x \times y)\]

Answer 19

So multiply 3 and x.?

Answer 20

\[\huge\rm log_2(3)+\log_2 x=3\] like this OR
yes right!!

Answer 21

that's how we should condense log equations
\[\huge\rm log_2 (3 \times x)=3\]
now we should convert log to exponential form