Question

here

Answer 1

@jtvatsim

Answer 2

5(a) doesn't look too bad. You could assume without loss of generality that y > z, that is, y = z + r for some r > 0, and show that the given expression yields y for max(y,z) and z for min(y,z).

Answer 3

5(b) should follow quickly from 5(a)... but I haven't looked at it in depth.

Answer 4

@jtvatsim

Answer 5

thats my book

Answer 6

OK, thanks.

Answer 7

I should definitely be able to get a proof for 4. There is one in my book that I can probably use.

Answer 8

ok

Answer 9

what about 3?

Answer 10

Haven't quite figured out what they are talking about yet... but I'm not giving up yet. :)

Answer 11

ok. thanks

Answer 12

Here is my attempted proof for problem 4. I'm mentally tired right now, so I'll take a look at problem 3 later. Hope this first proof helps! :)