is x=6 extranous or no
@taramgrant0543664
where is the equation?
you want me to make one lol
ok good!! what did you do thus far?
igt x=6
but ineed to know if its extranous or not
well put it back into the equation and see if it does work? if we put six what is the problem?
It does not really work does it?
that will produce division by zero yes? which is not allowed
you agree or disagree? what is your stance?
hhhh well can we divide by 0 can we have 6/0 in the left in the right 6/0-6/2
what is 6/0? can you have an answer?
not so not extanrous
ok once step at a time what is extraneous solution
let me answer this, it is a solution that you find by correct algebraic maneuvers but it does not work for the equation when we put it back
An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.
yeah that's the definition right there so from the start x=6 is excluded from domain yes
but when you were solving the equation to transform it using some maneuvers then you got x=6
that's why we say it is extraneous solution because it is not included in the domain
here is what we do \[\frac{x}{x-6}=\frac{x}{x-6}-\frac{6}{2}\] domain here is every real number except 6
slight mistake first should be 6/x-6
so \[\frac{6}{x-6}=\frac{x}{x-6}-\frac{6}{2}\] \[\frac{6}{x-6}=\frac{2x-6}{2(x-6)}\] \[\frac{6}{\cancel {x-6}}=\frac{2x-6}{2\cancel{(x-6)}}\] \[6=\frac{2x-6}{2}\Longrightarrow 12 =2x-6 \Longrightarrow x=9\]
how did you got x=6?
i got 9
oh my bad i miss something
correct the solution found is x=6 just missed up above in line 2
so 6 we said excluded therefore it is extraneous
was that helpful? clear?
Join our real-time social learning platform and learn together with your friends!