Question

(cos Θ + cos Θ)^2 + (cos Θ + cos Θ)^2

answers are
sin2 Θ

4

8

cos2 Θ

Answer 1

SOMEONE PLEASE HELP

Answer 2

I just showed you this :\

Answer 3

Someone else isn't going to get a different answer...they will tell you your options are wrong as well, we got \[8 \cos^2(\theta)\]

Answer 4

yes but i was hoping someone cou;d help me answer it maybe theres a different way

Answer 5

\[(\cos(\theta)+\cos(\theta)^2 = (2\cos \theta)^2 = 4\cos^2(\theta)\] since both sides are same we have \[4\cos^2(\theta)+4\cos^2(\theta) = 8\cos^2(\theta)\]

Answer 6

Your options don't make sense, either you just pick one at random or email your teacher

Answer 7

okay i think im going to go with 8

Answer 8

Post the full question

Answer 9

Maybe you missed a detail

Answer 10

Including everything

Answer 11

Yeah ok the options are wrong, go either 8 or cos^2theta I guess :\ make sure to tell your teacher

Answer 12

tahts all it is

Answer 13

do you mind helping w another

Answer 14

sure

Answer 15

what is the sine value of 5pi/3

Answer 16

i know its equal to 300 degrees

Answer 17

?

Answer 18

\[\sin(5 \pi/3) \] ok so we have this, the reference angle here is pi/3 what's the ratio of sin(theta)?

Answer 19

im not sure

Answer 20

im sorry im really bad at math i just know tis equal to 300 degrees

Answer 21

SOH CAH TOA

Answer 22

that ring a bell?

Answer 23

\[\sin( \theta) = \frac{ opposite }{ hypotenuse } = \frac{ x }{ r }\]

Answer 24

oh yeah

Answer 25

this is the pi/3 triangle, so far so good?

Answer 26

yes

Answer 27

Ok since we know it's 300 degrees we know it's in the fourth quadrant of unit circle right. So\[y=-\sqrt{3}\]and\[r = 2\]\[\frac{ y }{ r } = \frac{ - \sqrt{3} }{ 2 }\] sorry I put x as opposite when it should be y/r and not x/r.

Answer 28

okay

Answer 29

So that's our exact value

Answer 30

thank you so much

Answer 31

Np