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Mathematics 8 Online
OpenStudy (anonymous):

Which data set has the greatest spread for the middle 50% of its data? {18, 13, 22, 17, 21, 24} {17, 19, 22, 26, 17, 14} {13, 17, 12, 21, 18, 20} {18, 21, 16, 22, 24, 15}

OpenStudy (tkhunny):

You should find the middle 50% of the data for each set.

OpenStudy (anonymous):

I figured that much on my own, why is the middle 50% though?

OpenStudy (anonymous):

*what

OpenStudy (tkhunny):

There are 6 items in each set. 50% of 6 is 3. Order the sets and pick the middle 3.

OpenStudy (anonymous):

13,17,18,21,22,24 14,17,17,19, 22,26 12,13,17,18,20,21 15,16,18, 21,22,24

OpenStudy (tkhunny):

Nicely ordered. Now pick the middle three from each.

OpenStudy (anonymous):

they each have 6 numbers, there isn't a middle three, two of them are in the middle

OpenStudy (anonymous):

@nincompoop

OpenStudy (anonymous):

@Hero

OpenStudy (tkhunny):

Well, you must decide if you will take 2 or 4. Which actually contains the middle 50%? It is a common problem with small datasets.

OpenStudy (anonymous):

so the middles would be 18, 21 17,19 17,18 and 18, 21

OpenStudy (tkhunny):

That does not contain 50%.

OpenStudy (anonymous):

huh?

OpenStudy (tkhunny):

You must use AT LEAST 50% of the data. Picking the middle 2 is only 1/3 of the data. You'll have to go up to 2/3.

OpenStudy (anonymous):

okay so the middle two are 21,22 19,22 18,20 and 21,22

OpenStudy (tkhunny):

... and that is not helpful because you are examining only the middle 1/3. You need 1/2 AT LEAST.

OpenStudy (anonymous):

shouty capitals are not helpful, so what you mean is I need at least half of those numbers to examine?

OpenStudy (tkhunny):

It's not shouty. It's just emphasis. Perhaps a different approach. Can you find the median of each dataset?

OpenStudy (anonymous):

that I can do

OpenStudy (tkhunny):

Do you get 21.5, 20, 19, and 21.5?

OpenStudy (anonymous):

yes

OpenStudy (tkhunny):

Okay, how about the medians of the two subsets created by those medians? In other words, given {18, 13, 22, 17, 21, 24} Sorted: 13, 17,18, 21, 22, 24 Median: 19.5 Left subset: 13 17 18 ==> Median 17 Right subset 21 22 24 ==> Median 22 Make any sense?

OpenStudy (anonymous):

makes sense

OpenStudy (tkhunny):

Well, what we have just created is this list: 25th percentile = 17 50th percentile = 19.5 = Median 75th percentile = 22 Comparing the 75th to the 25th creates the "Interquartile Range". Notice how 75% - 25% = 50%. Thus, it is possible that the "middle 50% of the data" simply means the interquartile range. 22 - 17 = 5 Is this greater than or less than the interquartile range of the other sets?

OpenStudy (anonymous):

greater than

OpenStudy (tkhunny):

I believe you, but I have not calculated them. The difficulty is what is meant by "middle 50% of the data". Originally, I was interpreting that literally and it was confusing. When I decided it might just mean the Interquartile Range, we had something that could be understood and solved.

OpenStudy (anonymous):

so which set has the greatest spread

OpenStudy (tkhunny):

You tell me. Which has the greatest interquartile range? I did the first set.

OpenStudy (anonymous):

I think its b

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