Question

You are in a hot-air balloon that, relative to the ground, has a velocity of 6.65 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 2.88 m/s. What are (a) the magnitude and (b) direction of the hawk's velocity relative to the ground? Express the directional angle relative to due east.

Answer 1

Use pythagorean theorem to find magnitude
and use \[\tan^{-1} (\frac{ y }{ x })\]
to find the angle

Answer 2

you there @neelam.khindria ?

Answer 3

Is it correct? @arindameducationusc

Answer 4

Never got tested on relative velocity or acceleration.

Answer 5

theta=tan inverse(y/x)
yes @Shalante you are right....

Answer 6

Thanks for the response

Answer 7

thanks guys!