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Mathematics 7 Online
OpenStudy (mathmath333):

Probability question.

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}& \normalsize \text{A box contains 10 red marbles, 20 blue marbles and 30 green marbles}\hspace{.33em}\\~\\ & \normalsize \text{5 marbles are drawn from the box}\hspace{.33em}\\~\\ & \normalsize \text{what is the probability that } \hspace{.33em}\\~\\ & \normalsize \text{(i) atleast one will be green?}\hspace{.33em}\\~\\ \end{align}}\)

ganeshie8 (ganeshie8):

may be work the probability for "none will be green" then subtract that from 1

OpenStudy (mathmath333):

phi is a person , he is not a method

OpenStudy (mathmath333):

but substracting from (1- "none will be green") Will resemble all will be green

ganeshie8 (ganeshie8):

whats the negation of "none of them are green" ?

ganeshie8 (ganeshie8):

do you say "none of them are green" to below set ? {B R B R G B} ?

OpenStudy (mathmath333):

All will be green ? Or At least one will be green . i am confused

OpenStudy (mathmath333):

\(\color{blue}{\text{Originally Posted by}}\) @ganeshie8 do you say "none of them are green" to below set ? {B R B R G B} ? \(\color{blue}{\text{End of Quote}}\) one G is green.

ganeshie8 (ganeshie8):

negation of "none of them are green" is "at least one of them is green"

OpenStudy (mathmath333):

ok my english / logic is weak.

ganeshie8 (ganeshie8):

your english/logic is fine, it takes some to see why above is true lets do some examples may be

OpenStudy (mathmath333):

ok

ganeshie8 (ganeshie8):

whats the opposite of statement : "all of them are green"

ganeshie8 (ganeshie8):

whats the opposite of statement : "all of them did good"

OpenStudy (mathmath333):

none of them is green

ganeshie8 (ganeshie8):

wrong

OpenStudy (mathmath333):

y

ganeshie8 (ganeshie8):

opposite of "all of them are green" is "not all of them are green" which is same as "at least one of them is not green"

OpenStudy (mathmath333):

ohk

ganeshie8 (ganeshie8):

lets do couple more quick examples

ganeshie8 (ganeshie8):

whats the opposite of "at least one of my shirts is red"

OpenStudy (mathmath333):

None of my shirts is red

ganeshie8 (ganeshie8):

good, whats the opposite of "all of my shirts are blue"

OpenStudy (mathmath333):

all of my shirts are not blue

ganeshie8 (ganeshie8):

do you mean : "there is at least one shirt that is not blue" ?

OpenStudy (mathmath333):

ya this one

ganeshie8 (ganeshie8):

good are you confident or want to do couple more ?

OpenStudy (mathmath333):

confident

ganeshie8 (ganeshie8):

so from probability rules you must be knowing that \[P(A) + P(A)' = 1\]

OpenStudy (mathmath333):

yes

ganeshie8 (ganeshie8):

In our case, \(P(A)\) : at least one of them is green \(P(A)'\) : ?

OpenStudy (mathmath333):

none of them is green

ganeshie8 (ganeshie8):

good, find its probability

OpenStudy (mathmath333):

=1-(30C5)/(60C5)

ganeshie8 (ganeshie8):

Perfect!

ganeshie8 (ganeshie8):

that is correct, but could you explain how you got that ?

OpenStudy (mathmath333):

p'(a)=1-p(a) p(a)=none of them is green

ganeshie8 (ganeshie8):

looks good!

ganeshie8 (ganeshie8):

do you double check ur answer by working it using an alternative method ?

OpenStudy (mathmath333):

as per probablity the chance of getting 1 from dice is 1/6 so is it true that if i threw a dice 6 times there will be 1 at least

OpenStudy (mathmath333):

no i check by back of the book

ganeshie8 (ganeshie8):

probability is never "exactly" true

ganeshie8 (ganeshie8):

we say that seeing "1" at least once is more likely when you threw a dice 6 times

ganeshie8 (ganeshie8):

sometimes you might not get a single 1 even if you throw it 100 times that can happen

OpenStudy (mathmath333):

ok so its not true

ganeshie8 (ganeshie8):

yes, you can't use probability to win bets

OpenStudy (mathmath333):

yep

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