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Mathematics 18 Online
OpenStudy (mathmath333):

Probablity question

OpenStudy (mathmath333):

In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (a) one ticket (b) two tickets (c) 10 tickets

Nnesha (nnesha):

lol 100% of not getting a prize for meh :P bad luck :P

OpenStudy (welshfella):

P(winning with one ticket) = 10/1000 = 0.001

OpenStudy (mathmath333):

so (a.) not winning a ticket =990/1000 ?

OpenStudy (welshfella):

9990/10.000 = 0.999

OpenStudy (mathmath333):

but 1-10/1000=990/1000

OpenStudy (mathmath333):

u earlier said P(winning with one ticket) = 10/1000

OpenStudy (welshfella):

its 10 over 10 thousand

OpenStudy (welshfella):

yea that was a mistake should be 10 / 10,000

OpenStudy (mathmath333):

ok

OpenStudy (sohailiftikhar):

yes there is a probability

OpenStudy (sohailiftikhar):

it's c

OpenStudy (sohailiftikhar):

probability not getting prize is 10/10,000

OpenStudy (kropot72):

If you buy 2 tickets, the probability of not getting a prize is given by \[\large \frac{9990C2}{10000C2}=0.998\] If you buy 10 tickets, the probability of not getting a prize is given by \[\large \frac{9990C10}{10000C10}=0.99\]

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