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OpenStudy (mathmath333):
In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded.
What is the probability of not getting a prize if you buy (a) one ticket (b) two
tickets (c) 10 tickets
Nnesha (nnesha):
lol 100% of not getting a prize for meh :P
bad luck :P
OpenStudy (welshfella):
P(winning with one ticket) = 10/1000 = 0.001
OpenStudy (mathmath333):
so (a.) not winning a ticket =990/1000 ?
OpenStudy (welshfella):
9990/10.000 = 0.999
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OpenStudy (mathmath333):
but
1-10/1000=990/1000
OpenStudy (mathmath333):
u earlier said P(winning with one ticket) = 10/1000
OpenStudy (welshfella):
its 10 over 10 thousand
OpenStudy (welshfella):
yea that was a mistake should be 10 / 10,000
OpenStudy (mathmath333):
ok
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OpenStudy (sohailiftikhar):
yes there is a probability
OpenStudy (sohailiftikhar):
it's c
OpenStudy (sohailiftikhar):
probability not getting prize is 10/10,000
OpenStudy (kropot72):
If you buy 2 tickets, the probability of not getting a prize is given by
\[\large \frac{9990C2}{10000C2}=0.998\]
If you buy 10 tickets, the probability of not getting a prize is given by
\[\large \frac{9990C10}{10000C10}=0.99\]