Question

In an electric circuit, the reciprocal of the total capacitance of two capacitors in a series in the sum of reciprocals of the capacitances. Find the total capacitence of two capaciatances of 0.0050 F and 0.0040 F connected in series.
The total capacitance of the two capacitances is??

Answer 1

\[\frac{ 1 }{ C_{eq} }=\frac{ 1 }{ C_1 }+\frac{ 1 }{ C_2 }\]

Answer 2

\(C_1\) and \(C_2\) are the given capacitances and \(C_{eq}\) is what you're solving for

Answer 3

So can you help me get my solution to get the answer

Answer 4

Do i need to divide or multipy?

Answer 5

you need to add the two fractions, then the answer will be the reciprocal

Answer 6

So I get .009 when I add 0.0050 and 0.0040 together

Answer 7

put .005 in for C_1 and put .004 in for C2 so you should have

\[\frac{ 1 }{ .005 }+\frac{ 1 }{ .004 }\]
add this, then take the reciprocal

Answer 8

\[\frac{ 1 }{ 450 }\] ?

Answer 9

right

Answer 10

So now what to get my answer??

Answer 11

1/450 is the answer