A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H(t) = −16t2 + vt + s, approximately how long will it take the firecracker to hit the ground? Eight seconds Nine seconds 10 seconds 11 seconds
@LiveLaughDie @Nnesha @pooja195
what is s?
im not sure @sohailiftikhar
it should be some constant value like 5,3 etc u checked the statement clearly ?
take is 5 ..now out height H=0 to find the time 0=-16t^2+vt+5
now 16t^2-vt=5 put value of v from given data v=110fet/sec 16t^2-110t=5 divide whole equation with 16 to get simplest form
16t^2=5+110 16T^2=115 is tis correct?
no where is the t with 110 ?
? could you just show me for my understudying @sohailiftikhar
just find the value of t from the equation which i gave you ignor negative value and get +ve value that will be the answer
t=2.680951
@sohailiftikhar
did u do your work correctly ? what two values you have got ? for t
-2.680951
there ya goooo @sohailiftikhar
ok it's correct
ok I'm still not sue what the answer is :/ @sohailiftikhar
lol we are not sure about s which we taken as 5 ..so take it easy it's 2 sec
that not one of the answers :( @sohailiftikhar
so what is answer ?O.o
10? @sohailiftikhar
lol what ? no it can be possible it only can 2 or near it your answer is correct i'm sure ..from where u get this huh ?
here are the options: Eight seconds Nine seconds 10 seconds 11 seconds
setup the equation when it hits the ground h(t)=0 n v=110 and s=150 now plug in the numbers and solve the qudratic equation
ok
so im solving for s?
no solve for t they already gave you v and s value
what are they ?
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha setup the equation when it hits the ground h(t)=0 n v=110 and s=150 now plug in the numbers and solve the qudratic equation \(\color{blue}{\text{End of Quote}}\) read this
ook so what would the formula be to solve for t ?
\[\huge\rm \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] quadratic formula
a , b ,c values are \[\huge\rm Ax^2+Bx+C=0\] A= leading coefficient b=middle term c= constant term
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