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A 4kg ball is dropped from a heught of 15 m from the floor, what is the kinetic energy when it strikes the floor? Use conservation of energy
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What kind of energy do you think the ball has before it's dropped?
first find P.E throw mgh
mgh=P.E
4*9.8*15
(4)(15)(10)=600 take g=10m/s^2
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for accurate value g=9.8m/s^2 (4)(15)9.8=closer to 600m/s
as total energy remains conserved so at max height all energy equal to P.E and K.E=0 and at closer to ground all energy is K.E and P.E=0 but total energy remain same so your .K.E will also be (4)15)(9.8)=?
588 J ?
yes
thank you :)
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