Using the equation, 4Fe + 3O2 → 2Fe2O3, if 111.6 g of iron react, what mass of oxygen was consumed?

32.00 g

47.96 g

96.06 g

111.6 g

Question

Using the equation, 4Fe + 3O2 → 2Fe2O3, if 111.6 g of iron react, what mass of oxygen was consumed?
		
32.00 g
		
47.96 g
		
96.06 g
		
111.6 g

abhisar · Answer

Hi!

From your equation you can see that 4 moles of iron (56*4=224 grams)need 3 moles of $\sf O_2$ (32*3=96 grams), so for each gram of iron 96/224 = 0.428 grams of $\sf O_2$ is needed. Now using unitary methods you can easily calculate amount of $\sf O_2$ consumed for 111.6 grams of iron.

abhisar · Answer

Is it clear now?