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Mathematics 14 Online
OpenStudy (anonymous):

am i correct

OpenStudy (anonymous):

OpenStudy (mathstudent55):

Notice that each choice has the % sign in it. 6% in 1 year (12 months) is what percent in 1 month?

OpenStudy (anonymous):

okay but can you say if im correct or not please

OpenStudy (mathstudent55):

You are not correct.

OpenStudy (mathstudent55):

6% in 12 months is ? in 1 month?

OpenStudy (anonymous):

ok so my second option was d so is d correct ? iwill fan and medal you

OpenStudy (mathstudent55):

Correct. 6%/12 months = 0.5%/1 month

OpenStudy (anonymous):

thanks bro!

OpenStudy (anonymous):

@mathstudent55

OpenStudy (mathstudent55):

yw

OpenStudy (anonymous):

OpenStudy (anonymous):

@mathstudent55 am icorrect here too

OpenStudy (anonymous):

@mathstudent55

OpenStudy (mathstudent55):

You are correct.

OpenStudy (mathstudent55):

This question is a bit strange. Up to step 3, the problem is 100% correct. In step 4, decimals were written for the logs. Step 4 may or may not be a mistake depending on whether an exact answer or an approximation is asked for. Step 5 is definitely incorrect because the division of the decimals on the right side is incorrect. If there is no choice of Step 5, then step 4 has to be the error, but I don't agree with the question.

OpenStudy (mathmate):

@jammy987 On the first question, the question asks the rate of "decay"each month, which is a hint that the decay is cumulative, which accumulates over a year to give a depreciation of 6%, or 0.94 of the previous year. Therefore we need to solve for k in (1-k)^12=(1-0.06) take the twelfth root on both sides, (1-k)=(0.94)^(1/12)=0.994857 k=1-0.994857=0.005143. Check: (1-0.005143)^12=0.940000=depreciation of 6%

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